The Scale On A Drawing Is 1 Mm = 3 M. How Many Meters Does 2 Centimeters Represent?

3 Calibration drawings

Have you ever drawn a plan of a room in your firm to assist yous work out how to rearrange the furniture? Or maybe yous've sketched a plan of your garden to help you decide how big a new patio should be?

These pictures are called calibration drawings. The important thing with scale drawings is that everything must be drawn to scale, meaning that everything must exist in proportion – that is, 'shrunk' past the aforementioned amount.

All scale drawings must have a calibration to tell us how much the drawing has been shrunk past.

Case written report _unit5.3.ane Example: In the garden

Here is an example of typical scale drawing:

Described image

Figure _unit5.3.ane Effigy 16 A scale drawing of a garden

What'south the width and length of the patio?

Box _unit5.3.one

Hint: This calibration drawing has been drawn on squared paper. This makes it easier to draw and understand. Each square is 1 cm wide and 1 cm long. So instead of using a ruler you can only count the squares and this volition tell yous the measurement in centimetres.

Method

The calibration in this drawing is 1:100. This ways that i cm on the scale drawing is equal to 100 cm, or 1 m, in real life. Once we know the scale, we can measure the distances on the drawing.

Using a ruler (or only counting the squares), nosotros find that the patio is 5 cm long and three cm wide on the drawing. This means that in existent life it is 5 metres long and 3 metres wide.

So when you're working with calibration drawings:

Notice out what the calibration on the drawing is.
Measure the distance on the drawing using a ruler (or count the number of squares, if that's an option).
Multiply the distance you measure past the calibration to requite the distance in real life.

At present try the following action. Call up to check your answers in one case you have completed the questions.

Activity _unit5.three.1 Activity 6: Getting information from a calibration drawing

Let's stay with this scale drawing of the garden.

Effigy _unit5.3.two Figure 17 A scale drawing of a garden
- a.What is the width and length of the vegetable garden?
- b.What is the width and length of the blossom bed?
- c.How far is the patio from the vegetable garden?
- d.Say y'all wanted to put a trampoline between the patio and the vegetable garden. Information technology measures 3 m past 3 m. Is there plenty space for information technology?
A landscaper wants to put a wild area in your garden. She makes a scale plan of the wild area:

Effigy _unit5.3.three Effigy 18 A scale drawing of a wild area of a garden

What is the length of the longest side of the actual wild surface area in metres?
Here is a scale cartoon showing one disabled parking space in a supermarket auto park. The supermarket plans to add two more disabled parking spaces next to the existing one, with no spaces between them.

Figure _unit5.iii.four Figure 19 A scale drawing of a car park

What will exist the total actual width of the three disabled parking spaces in metres?

Respond

The answers are every bit follows:
- a.The vegetable garden is 5 m long and 2 m wide.
- b.The flower bed is half dozen 1000 long and 2 m broad.
- c.The patio and vegetable garden are three m apart.
- d.The distance betwixt the patio and vegetable garden is iii m and the trampoline is 3 chiliad wide. So the trampoline would fit in the space, but it would be a flake of a squeeze.
The length on the drawing is 9 cm, and the scale is ane:50. This means that 1 cm on the drawing is equal to 50 cm in existent life. And then to find out what nine cm is in existent life, you need to multiply it past fifty:
- 9 × fifty = 450 cm
The question asks for the length in metres, so you need to catechumen centimetres into metres:
- 450 ÷ 100 = 4.5 m
The actual length of the wild area will be iv.5 m.
Y'all need to find out the width of 3 disabled parking spaces. The width of one parking space on the calibration drawing is 2 cm, so offset you need to multiply this past iii:
- 2 × three = 6 cm
The calibration is 1:125. This means that 1 cm on the drawing is equal to 125 cm in existent life. So to find out what six cm is in existent life, you lot need to multiply information technology past 125:
- 6 × 125 = 750 cm
The question asks for the length in metres, so you need to convert centimetres into metres:
- 750 ÷ 100 = seven.v m
The actual width of all 3 parking bays will be 7.5 m.